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3 years ago

Pls help! I will mark brainliest

Mathematics

1 answer:

dolphi86 [110]3 years ago

6 0

Answer:

So the greatest common factor is 3 for sure

Step-by-step explanation:

54x^4y^5z^2

i could be wrong but i am sure that's it

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Given: △DMN, DM=10 3 m∠M=75°, m∠N=45° Find: Perimeter of △DMN

OlgaM077 [116]

Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...

... 30-60-90: 1 : √3 : 2

... 45-45-90: 1 : 1 : √2

The long side of ΔMDX is 10√3, so the other two sides are

... MX = MD(√3/2) = 15

... DX = MD(1/2) = 5√3

The short side of ΔMNX is MX = 15, so the other two sides are

... NX = MX(1) = 15

... MN = MX(√2) = 15√2

Then the perimeter of ΔDMN is ...

... P = DM + MN + NX + XD

... P = 10√3 +15√2 + 15 + 5√3

... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN

5 0

3 years ago

You have 2 nickels, 11 dimes and 5 quarters in your pocket. What is the ratio of nickels to quarters?

daser333 [38]

Answer:

2:5

Step-by-step explanation:

Since there are 2 nickles and 5 quarters there are 2 nickles for every 5 quarters so answer is 2:5

4 0

3 years ago

A test is used to assess readiness for college. In a recent year, the mean test score was 20.3 and the standard deviation was 4

Vlada [557]

Answer:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.

For this case we have the mean and the deviation given:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

6 0

3 years ago

Help with geometry will mark brainliest for correct anwsers

Veseljchak [2.6K]

The first one is (-2,1)
The other one is 36

4 0

3 years ago

Hcf and LCM of 391 and 236

mash [69]

Answer:

LCM = 92276

HCF = 1

Step-by-step explanation:

5 0

2 years ago