Answer:
![y = - \frac{3}{2}x + 2](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B2%7Dx%20%20%2B%202)
Step-by-step explanation:
Assuming the question wants you to write and equation passing through (2,-1); and parallel to y=-3/2x+6.
Then we use the slope intercept form:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
We substitute the point and slope to get:
![y - - 1 = - \frac{3}{2} (x - 2)](https://tex.z-dn.net/?f=y%20-%20%20-%201%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%28x%20-%202%29)
![y + 1 = - \frac{3}{2}x - + 3](https://tex.z-dn.net/?f=y%20%20%2B%201%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B2%7Dx%20-%20%2B%203)
![y = - \frac{3}{2}x + 3 - 1](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B2%7Dx%20%20%2B%203%20-%201)
![y = - \frac{3}{2}x + 2](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B2%7Dx%20%20%2B%202)
Note that parallel lines have the same gradient.
Answer:
Option :" Use distance formula to prove that the lengths of the diagonals are equal" is correct
Step-by-step explanation:
Option : Use distance formula to prove that the lengths of the diagonals are equal" is correct.
Because " By using the coordinate geometry to prove that the diagonals of the rectangle are congruent, first we have to find the lengths of the top and bottom of the rectangle and then solve it for the lengths of the diagonals by using the distance formula".
Answer: x=-1
Step-by-step explanation: