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damaskus [11]
3 years ago
6

Find the slope of the line whose equation is 5y = x - 3. a)-3 b)-3/5 c)1/5 d)5

Mathematics
2 answers:
Wewaii [24]3 years ago
3 0
Y=mx+b
m=slope
solve for y

5y=x-3
divide both sides by 5
y=(1/5)x-(3/5)
slope=1/5


C is answer
defon3 years ago
3 0
Y = 1/5x - 3/5

Slope = 1/5 (c)
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Write an equation in slope-intercept form for the line that passes through (1,9) and (3,5).
kozerog [31]

Answer:

The answer to your question is    y = -2x + 11

Step-by-step explanation:

A (1, 9)

B (3, 5)

- Find the slope

 m = \frac{y2 - y1}{x2 - x1}

 m = \frac{5 - 9}{3 - 1}

 m = \frac{-4}{2}

        m = - 2

- Find the line equation

        y - y1 = m (x - x1)

        y - 5 = -2(x - 3)

        y - 5 = -2x + 6

        y = -2x + 6 + 5

        y = -2x + 11

8 0
3 years ago
Read 2 more answers
Q1. An airplane flies with a constant speed of 600 miles per hour. How far can it travel in 3 1/2 hours?
Dahasolnce [82]

Answer:

Q1. 1050 miles

Q2. 1h 30m

Step-by-step explanation:

Q1. 1h = 300 miles

3\frac{1}{2}h = 3.5 × 300 miles

     = 1050 miles

Q2. 68km = 1h

102km = \frac{102}{68} × 1h

           = 1.5h

           = 1h 30m

5 0
3 years ago
Find the area (shaded) and round to the tenths place if necessary.
fomenos

Answer:

9π - 9

Step-by-step explanation:

Depends on what the question stated was pi (π). The area of the circle is 9(3 squared) * π. the shaded area is the area of the circle - the area of the triangle. The area of the triangle is base * high / 2. If the diameter of the circle (6) is what we use as the base, then 3 would be the high, making the area 9. This means the shaded area would be 9π - 9.

6 0
3 years ago
14 less than 6 times a number
mestny [16]

Step-by-step explanation:

14 < 6×?

6×3=18

therefore anything above 3 multiplied by 6 would be greater in value than 14

8 0
3 years ago
An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiveness of the new meth
Anna35 [415]

Answer:

With 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

Step-by-step explanation:

We are given that the effectiveness of the new method was evaluated in a simulation study. In 50 simulations, the mean improvement in traffic flow in a particular intersection was 655.6 vehicles per hour, with a standard deviation of 311.7 vehicles per hour.

A traffic engineer states that the mean improvement is between 583.1 and 728.1 vehicles per hour.

<em>Let </em>\bar X<em> = sample mean improvement</em>

The z-score probability distribution for sample mean is given by;

            Z =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean improvement = 655.6 vehicles per hour

            \sigma = standard deviation = 311.7 vehicles per hour

            n = sample of simulations = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the mean improvement is between 583.1 and 728.1 vehicles per hour is given by = P(583.1 < \bar X < 728.1) = P(\bar X < 728.1) - P(\bar X \leq 583.1)

  P(\bar X < 728.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{728.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z < 1.64) = 0.9495

  P(\bar X \leq 583.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{583.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z \leq -1.64) = 1 - P(Z < 1.64)

                                                            = 1 - 0.9495 = 0.0505                      

<em />

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.64 in the z table which has an area of 0.9495.</em>

Therefore, P(583.1 < \bar X < 728.1) = 0.9495 - 0.0505 = 0.899 or 89.9%

Hence, with 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

6 0
3 years ago
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