[ p+9 ]= 11
pretend that there is a +1 in front of the bracket
1 [ p+9 ]= 11
multiply the bracket by 1
(1)(p)=p
(1)(9)=9
p+9=11
move +9 to the other side
sign changes from +9 to -9
need to get p by itself
p+9-9=11-9
p=11-9
answer:
p=2
Answer:
(2x-7)(x-3)
Step-by-step explanation:
Answer:
bgfadnjsaflkdjkfsdjbehheheh
Step-by-step explanation:
Answer:
The pattern is this: I create a function p(x) such that
p(1)=1
p(2)=1
p(3)=3
p(4)=4
p(5)=6
p(6)=7
p(7)=9
Therefore, trivially evaluating at x=8 gives:
p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)
Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
