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2 years ago

How do i solve 125 to the power of two thirds without using a calculator

2 answers:

6 0

125^2/3
Think of it like this cube root (125^2)
So square 125 which is 125*125 or 15625
Then take the cube root of that: 25.

Harrizon [31]2 years ago

5 0

Here is your answer and result

Have a good day

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-2x^2 + 4x + 16 in vertex form

Reil [10]

Answer:

y = - 2(x - 1)² + 18

Step-by-step explanation:

- 2x² + 4x + 16 ← factor out - 2 from the first 2 terms

= - 2(x² - 2x) + 16

using the method of completing the square

add/subtract ( half the coefficient of the x- term)² to x² - 2x

= - 2(x² + 2(- 1)x + 1 - 1) + 16

= - 2(x - 1)² + 2 + 16

= - 2(x - 1)² + 18 ← in vertex form

6 0

2 years ago

A colony of fruit flies exhibits exponential growth. suppose that 500 fruit flies are present. let p(t) denote the number of fru

murzikaleks [220]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.

Part A:
The differential equation is:
y '= 0.08y
The initial condition is:
P (0) = 500

Part B:
The formula for this case is:
P (t) = 500exp (0.08 * t)

Part C:
After five days we have to evaluate t = 5 in the equation.
We have then:
P (5) = 500 * exp (0.08 * 5)
P (5) = 745.9123488
Rounding:
P (5) = 746

4 0

3 years ago

Which fraction is equivalent to g?<br> 24<br> 4<br> o<br> 40

Gennadij [26K]

Answer:

vtvgjvvuctucytcuyvuyvuy

Step-by-step explanation:

7 0

3 years ago

Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.

andrezito [222]

The value added to the equation $$x^2-6x=1$ exists $$x^2-6x+9=10$ .

<h3>What is a perfect square?</h3>

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

$(a$ ± $b)^2$ = $a ^2$ ± 2ab + $b ^2$

$$x^2-6x=1$

$x^2-2*3x=1$

then $$2ab = 2 * 3*x = 2 * x *3$

The value of a = x and b = 3

$$b^2=3^2=9$

$$x^2-6x+9=1+9$

$$x^2-6x+9=10$

The value added to the equation $$x^2-6x=1$ exists $$x^2-6x+9=10$ .

To learn more about perfect square refer to: brainly.com/question/6946048

#SPJ4

3 0

2 years ago

Please help!! Double points! write the ratios for sin X and cos X (Image attached)

Orlov [11]

Answer:

The ratio for sin(X) is $\frac{\sqrt{119} }{12}$

The ratio for cos(X) is $\frac{5}{12}$

Step-by-step explanation:

- The ratio of the sine of a right triangle is:

$sin(\alpha)=\frac{opposite-side}{hypotenuse}$

Since we need the ratio for angle X, $\alpha =X$ . From the picture we can infer that the opposite side of X is $\sqrt{119}$ . The hypotenuse (the side opposite to the right angle) is 12, so replacing the values:

$sin(X)=\frac{\sqrt{119} }{12}$

- The ratio of the cosine is:

$cos(\alpha)=\frac{adjacent-side}{hypotenuse}$

Similarly, $\alpha =X$ , adjacent side = 5, and hypotenuse = 12, so

$cos(X)=\frac{5}{12}$

6 0

3 years ago

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