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Car X can come with any of these 5 additional features: sunroof, stereo, tinted windows, leather seats and cruise control.
Quantity A
: Number of different combinations possible
Quantity B
: 25
A The quantity in Column A is greater
B The quantity in Column B is greater
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Answer:
A The quantity in Column A is greater
Explanation:
Lets first analyze the number of different combinations possible!
To find out the combinations we use the following formula:
The number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter.
![nCr=\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=nCr%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Car X can have these 5 features: sunroof, stereo, tinted windows, leather seats and cruise control.
Car X has 2 options for each feature: Included or Not included
If car X has no feature at all then:
![5C0=\frac{5!}{0!(5-0)!}=\frac{5!}{0!*5!}=1](https://tex.z-dn.net/?f=5C0%3D%5Cfrac%7B5%21%7D%7B0%21%285-0%29%21%7D%3D%5Cfrac%7B5%21%7D%7B0%21%2A5%21%7D%3D1)
If car X has 1 feature included then:
![5C1=\frac{5!}{1!(5-1)!}=\frac{5!}{1!*4!}=5](https://tex.z-dn.net/?f=5C1%3D%5Cfrac%7B5%21%7D%7B1%21%285-1%29%21%7D%3D%5Cfrac%7B5%21%7D%7B1%21%2A4%21%7D%3D5)
If car X has 2 features included then:
![5C2=\frac{5!}{2!(5-2)!}=\frac{5!}{2!*3!}=10](https://tex.z-dn.net/?f=5C2%3D%5Cfrac%7B5%21%7D%7B2%21%285-2%29%21%7D%3D%5Cfrac%7B5%21%7D%7B2%21%2A3%21%7D%3D10)
If car X has 3 features included then:
![5C3=\frac{5!}{3!(5-3)!}=\frac{5!}{3!*2!}=10](https://tex.z-dn.net/?f=5C3%3D%5Cfrac%7B5%21%7D%7B3%21%285-3%29%21%7D%3D%5Cfrac%7B5%21%7D%7B3%21%2A2%21%7D%3D10)
If car X has 4 features included then:
![5C4=\frac{5!}{4!(5-4)!}=\frac{5!}{4!*1!}=5](https://tex.z-dn.net/?f=5C4%3D%5Cfrac%7B5%21%7D%7B4%21%285-4%29%21%7D%3D%5Cfrac%7B5%21%7D%7B4%21%2A1%21%7D%3D5)
If car X has all of the 5 features included then:
![5C5=\frac{5!}{5!(5-5)!}=\frac{5!}{5!*0!}=1](https://tex.z-dn.net/?f=5C5%3D%5Cfrac%7B5%21%7D%7B5%21%285-5%29%21%7D%3D%5Cfrac%7B5%21%7D%7B5%21%2A0%21%7D%3D1)
Now sum all the possible combinations: 1+5+10+10+5+1=32
So, quantity A is 32 and quantity B is 25
Therefore, we can conclude that the quantity in column A is greater