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2 years ago

-5x-3.5 < 6.5 -5x <10 x >2

Mathematics

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:

x=3 ??i think

Step-by-step explanation:

cuz it makes sense like that

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Which expression is equivalent to r^m ÷ r^n? a. r^m − ^n b. r^m ^n c. r^m ⋅ ^n d. r^m ÷ ^n

Murljashka [212]

$r^m \div r^n= r^{m-n}$

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2 years ago

The slope of the line whose equation is 6x = 4y - 7 is 1. 4 2. 2/3 3. 3/2

OverLord2011 [107]

Answer:

3/2

Step-by-step explanation:

Divide by 4 to get 6x/4 = 3x/2

4 0

2 years ago

Read 2 more answers

Please help me with this math question.

JulijaS [17]

1.SA=10e^2
rectacgular prism=2e*e*e
cube=e*e*e
the length given is 2e=5
so
SA=5e^2
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4 0

2 years ago

This is part 2 plz help

Basile [38]

Answer:

Sorry dude I am a grade 4 that’s too hard

Step-by-step explanation:

6 0

2 years ago

Element X decays radioactively with a half life of 13 minutes. If there are 110 grams of Element X, how long, to the nearest ten

Vaselesa [24]

Answer : The time taken by the element to decay to 2 grams is, 75.2 minutes

Step-by-step explanation:

Half-life = 13 min

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{13\text{ min}}$

$k=0.0533\text{ min}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $0.0533\text{ min}^{-1}$

t = time passed by the sample = ?

a = initial amount of the reactant = 110 g

a - x = amount left after decay process = 2 g

Now put all the given values in above equation, we get

$t=\frac{2.303}{0.0533}\log\frac{110}{2}$

$t=75.2\text{ min}$

Therefore, the time taken by the element to decay to 2 grams is, 75.2 minutes

7 0

3 years ago