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Law Incorporation [45]
2 years ago
13

If for 5 pounds of beans it cost 4 dollars than how much money is needed for 50 pounds of beans

Mathematics
2 answers:
Sergio039 [100]2 years ago
8 0

Step-by-step explanation:

\sf 5 \: pounds \longrightarrow 4 \: dollars

\sf 1\: pounds \longrightarrow \dfrac{4}{5} \: dollars

\sf 50\: pounds \longrightarrow \dfrac{4}{5}×50 \: dollars

\sf \longmapsto 40 \: dollars

aleksley [76]2 years ago
3 0

Answer:

40 dollars

Step-by-step explanation:

We can use a ratio to solve the problem

5 pounds         50 pounds

----------------  = -----------------

4 dollars            x dollars

Using cross products

5 * x = 4 * 50

5x = 200

Divide by 5

5x/5 = 200/5

x = 40

40 dollars

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16.2 Jumping Rope
slava [35]

Answer:

Percentage of Diego's time is 75%.

Step-by-step explanation:

Given : Jumping Rope  hool held a jump-roping contest. Diego jumped rope for 20 minutes.  A school held a jur  Jada jumped rope  for 15 minutes.

To find : What percentage of Diego's time is that?​

Solution :

Diego jumped rope for 20 minutes.

Jada jumped rope for 15 minutes.

Percentage of Diego's time is given by,

\text{Percentage change}=\frac{\text{Jada time}}{\text{Diego time}}\times 100

\text{Percentage change}=\frac{15}{20}\times 100

\text{Percentage change}=75\%

Therefore, percentage of Diego's time is 75%.

7 0
3 years ago
What is the set of numbers for -9
Step2247 [10]

rational numbers and integers

8 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
3 years ago
Write 80% as a decimal.<br> I<br> help me??
Ghella [55]

Answer:

0.8

Step-by-step explanation:

6 0
3 years ago
The Stock Market nadia is a stockbroker. Earns 14​% commission each week. Last​ week, sold ​7200$ worth of stocks. How much did
elena-s [515]

Answer:

Step-by-step explanation:

C=0.14×7,200=1008

Nadia made a total of $1008 last week in commission sales

b). To express the total amount she made in 2011, we derive the formula below;

Total amount (2011)=Average weekly commission× number of weeks in 2011

where;

Average weekly commission=$1008

number of weeks in 2011=52

replacing;

Total amount (2011)=(1008×52)=52,416

The total amount Nadia in commission in 2011=$52,416

4 0
3 years ago
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