2 years ago

PLEASE ANSWER + BRAINLIEST !!!

Mathematics

1 answer:

denis23 [38]2 years ago

6 0

Answer:

I believe that the answer is D, I think I had this question but I can't really remember.

I hope this helps :) !

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Determine if the angles are greater than (>), less than (<), or equal (=) to each other.

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Opposite side to <XWY=XY

Here

WX=12
XY=15

WX<XY

$\\ \sf\longmapsto$

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2 years ago

What is the y value of the vertex 4x^2+8x-8

Oksana_A [137]

Answer:

The y-value of the vertex is $-12$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

In this problem we have

$f(x)=4x^{2}+8x-8$ -----> this a vertical parabola open upward

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+8=4x^{2}+8x$

Factor the leading coefficient

$f(x)+8=4(x^{2}+2x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

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$f(x)+12=4(x^{2}+2x+1)$

Rewrite as perfect squares

$f(x)+12=4(x+1)^{2}$

$f(x)=4(x+1)^{2}-12$

The vertex is the point $(-1,-12)$

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