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Anika [276]
3 years ago
6

PLEASE ANSWER + BRAINLIEST !!!

Mathematics
1 answer:
denis23 [38]3 years ago
6 0

Answer:

I believe that the answer is D, I think I had this question but I can't really remember.


I hope this helps :) !




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BRAINLIEST AND 30 POINTS FOR WHOEVER CAN EXPLAIN HOW TO GET THESE ANSWERS...
Dvinal [7]

Step-by-step explanation:

  • Since m∠ACM = 90°, then by angle addition, m∠ACP + m∠PCM = 90°.
  • Since CP⊥ AM, then by definition of perpendicular, m∠APC = 90°.  Since angles of a triangle add up to 180°, that means m∠PAC + m∠ACP = 90°.
  • By substitution, m∠PCM = m∠PAC.
  • Since m∠PCM + m∠CMP = 90°, then by substitution, m∠CMP = m∠PAC.
  • Therefore, by AAA, △ACP and △CMP are similar.

Having proven that the triangles are similar, we can write the proportion:

AP / CP = CP / MP

9 / CP = CP / 16

CP² = 144

CP = 12

Now, we can simply use Pythagorean theorem to find the other sides.

AC² = AP² + CP²

AC² = 9² + 12²

AC = 15

CM² = CP² + PM²

CM² = 12² + 16²

CM = 20

8 0
3 years ago
CAN SOMEONE PLEASE HELP ME???
vova2212 [387]
Answer:T


Step by Step explanation
8 0
2 years ago
Read 2 more answers
How many pages could I read per day for 4 weeks if the book has 292 pages?
Gemiola [76]
About 10 pages
If you divide 292 / 28 since there is 28 days in 4 weeks
7 0
3 years ago
Starting from the origin, how is point ( – 5, 4) plotted?
Feliz [49]
It’s gonna be 5 units left and 4 units up. Because 5 is going negative in the x axis and 4 is going positive in the y axis
8 0
3 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
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