0-60 haveagreatdaysirormaam
9514 1404 393
Answer:
E. 31.64
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation between the legs of a right triangle:
Tan = Opposite/Adjacent
You are given trig values for 36°. That means ...
tan(36°) = 23/x
x = 23/0.727 ≈ 31.64
Answer:
The maximum height is reached after 3.75 seconds.
Step-by-step explanation:
Assuming the deceleration due to gravity is unaided by air resistance, gravity causes the ball to lose vertical speed at the rate of 32 ft/s every second. The initial vertical speed of 120 ft/s will decline to zero when t satisfies ...
... 120 ft/s - (32 ft/s²)t = 0
... (120 ft/s)/(32 ft/s²) = t = 3.75 s
The ball will not go any higher after its vertical speed is zero.
Hey there!
ASSUMING:
4^3 / 2^3
IF SO:
4^3 / 2^3
= 4 * 4 * 4 / 2 * 2 * 2
= 16 * 4 / 4 * 2
= 64 / 4
= 64 ÷ 2 / 8 ÷ 2
= 32 / 4
= 32 ÷ 4
= 8
Therefore, the answer should be: 8
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
9514 1404 393
Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...

Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.