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sashaice [31]
3 years ago
12

What is the justification for step 2 in the solution process?

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

y = 11

Step-by-step explanation:

Solve for y

12y - 40 - 4y = 6y - 18

8y -40 = 6y - 18

8y - 6y - 40 = -18

2y - 40 = -18 ( the justification for step 2 is to isolate y on one side of the                   equation in order to solve for y )

2y - 40 + 40 = 40 - 18

2y = 22

2y/2 = 22/2

y = 11

Check :

12(11) - 40 - 4(11) = 6 (11) - 18

132 - 40 - 44 = 66 - 18

48= 48

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Answer:

D. Jessie needs to buy more eggs, flour, butter, and sugar.

Step-by-step explanation:

it is good to have more then none

4 0
2 years ago
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P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

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Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus
Ksivusya [100]

Given:

The given equation is:

16-3p=\dfrac{2}{3}p+5

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The value of p.

Solution:

We have,

16-3p=\dfrac{2}{3}p+5

Multiply both sides by 3.

3(16-3p)=3\left(\dfrac{2}{3}p+5\right)

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\dfrac{33}{11}=p

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2 years ago
1. The graph of every exponential function f(x)= ax, a>0, a≠1, passes through what three points(in terms of a)? Explain.
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8 0
3 years ago
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