Answer:
The length of side XZ should be greater than 10 and lesser than 60.
Step-by-step explanation:
In triangle XYZ ,
As
The length of side XY = 25 mm
The length of side YZ = 35 mm
Range of the third side can be computed when we already know the two sides of the triangle.
If subtracting , the 3rd side would have to be more than 10. Else 3rd side can not be made as two smaller legs will not meet.
and
If adding , the 3rd side would have to be less than 60. Else 3rd side will reach further than the the other two sides could reach.
Therefore, the length of side XZ should be greater than 10 and lesser than 60.
Answer:
2nd and 4th on edg
Step-by-step explanation:
3+21pi / 2 +4
3-21pi / 2 -4
There you go, you can eliminate the y’s cuz they equal 0 then just subtract like normal keeping the different variables separate.
see pic
Plot the intercepts:
y=-1
x=?
to find the x intercept, you dont solve the equation as it is solved in the slope-intercept form. instead, you simply plug in 0 for y:
0=1/4x-4
0=1/4x-4+4
4=1/4x
4/1/4=1/4x
1/4=0.25
x=16
revise:
y=(0, -1)
x=(16,0)
graph the slope for y=-1/2x-1: start from say point (0,-1)
graph the slope for y=1/4x-4: start from say point (16,0) ; you can just ise the intercept (0,-4) since the graph is diluted small...anyways
the points intersect at (4, -3) so thats the solution to the equations
NOTE: when graphing slopes that are negative either the numerator or the denominator can be graphed negative. so I graphed the first equation with the numerator as the positive and the denominator as the negative : rise= 1 ; run: -2. once i got to the end of the provided graph i started from the -1 y-intercept again and graphed the equation using: rise=-1; run=2
*graphing messes me up, too*