Answer: The answer is cosine of that acute angle.
Step-by-step explanation: We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.
In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.
Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.
Now, the ratio is given by
Thus, the ratio is cosine of the acute angle.
Answer:
$1300
Step-by-step explanation:
The extruder yields a revenue of $200per hour
Y denotes the number of breakdown per day.
The daily revenue generated is given as
R = 1600 - 50Y^2
We have an average of 2 breakdown per day
Lamda = 2
Represent lamda as β
E(Y) = β
E(Y(Y-1)) = β^2
E(Y^2) = E[Y(Y-1)] + E(Y)
= β^2 + β
E(R) = E(1600 - 50Y^2)
= 1600 - 50E(Y^2)
= 1600 - 50(β^2 +β)
Recall that β = lamda = 2
= 1600 - 50(2^2 + 2)
= 1600 - 50(4+2)
= 1600 - 50(6)
= 1600 - 300
= 1300
$1300
The expected daily revenue of the extruder is $1300
Answer:
x=2
y=1.732
Step-by-step explanation:
we use the formulae.....
SOHCAHTOA
where..Cos 60°=1/x
cos60=0.5
0.5=1/1
<u>X</u><u>=</u><u>2</u>
0.8660=y/2
y= 1.732
