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3 years ago

2.

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

Step-by-step explanation:

Consider the provided information.

A convex polygon is a polygon with all its interior angles less than 180°.

Regular polygon is a polygon in which all angles are equal and all sides are the same length.

An irregular polygon does not have congruent sides and interior angles.

From the above definitions we can identify the similarities and differences between the interior and exterior angles of both polygons.

Difference:

The interior angles of regular polygon are equal.

Since, the interior angles of a regular polygon are equal, the exterior angles must also be equal to one another.

The interior angle of irregular polygons are not equal, however, each exterior angle may have a different measurement as well.

Similarity:

The sum of interior angles for both polygon are equal. Also the sum of exterior angles for both polygon are equal.

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Aleonysh [2.5K]

Answer:

$=\left(-1,\:\frac{15}{2}\right)$

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\left(x_1,\:y_1\right)=\left(2,\:5\right),\:\left(x_2,\:y_2\right)=\left(-4,\:10\right)\\=\left(\frac{-4+2}{2},\:\frac{10+5}{2}\right)$

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3 years ago

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ikadub [295]

We have been given a system of nonlinear equations.

$\\y=40x^{2},y=19x+3$

In order to solve this system we can first equate the two equations in order to get a quadratic in x.

$\\40x^{2}=19x+3$

Our next step is to bring all the terms on one side.

$\\40x^{2}-19x-3=0$

Now we have to solve this equation. We can solve it by factoring using the splitting middle term method.

$\\40x^{2}-24x+5x-3=0$

$\\8x(5x-3)+(5x-3)=0$

$\\(8x+1)(5x-3)=0$

Upon setting each of these factors equal to zero using zero product property we get

$\\8x+1=0 \text{ or } 5x-3 = 0$

Upon solving both these equations we get

$\\x=-\frac{1}{8} \text{ or } x=\frac{3}{5}$

Now we can substitute these values of x in the equation

$y=19x+3$

We get

$\text{For }x=- \frac{1}{8} \Rightarrow y=19(- \frac{1}{8})+3= \frac{5}{8}\\$

$\text{For }x= \frac{3}{5}\Rightarrow y=19( \frac{3}{5})+3= \frac{72}{5}\\$

Therefore, our final set of solutions are

$(x,y)=(- \frac{1}{8},\frac{5}{8}) \text{ and } ( \frac{3}{5}, \frac{72}{5})$

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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