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Anvisha [2.4K]
3 years ago
5

2.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Step-by-step explanation:

Consider the provided information.

A convex polygon is a polygon with all its interior angles less than 180°.

Regular polygon is a polygon in which all angles are equal and all sides are the same length.

An irregular polygon does not have congruent sides and interior angles.

From the above definitions we can identify the similarities and differences between the interior  and exterior angles of both polygons.

Difference:

The interior angles of regular polygon are equal.

Since, the interior angles of a regular polygon are equal, the exterior angles must also be equal to one another.

The interior angle of irregular polygons are not equal, however, each exterior angle may have a different measurement as well.

Similarity:

The sum of interior angles for both polygon are equal. Also the sum of exterior angles for both polygon are equal.

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Factor the polynomial by it’s greatest common monomial factor. <br> 12k^3 - 30k^4
madam [21]

Answer:

6k^3(2 - 5k)

Step-by-step explanation:

12k^3 - 30k^4

Factor out 6k^3

6k^3(2 - 5k)

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If George received $78.00 for his work and he gets paid 6 dollars and hour how much is he getting paid
swat32

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Use the function below to find F(3).
arlik [135]

Answer:

The choice D.

Step-by-step explanation:

f(x) =  {( \frac{1}{6} })^{x}  \\  \\ f(3) =  {( \frac{1}{6} })^{3}  =  \frac{ ({1})^{3} }{( {6})^{3} }  =  \frac{1}{216}

7 0
2 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
[ANSWER ASAP PLEASE] Which point is a reflection of across the x-axis? A. point A B. point B C. point C D. point D E. point E​
Alex_Xolod [135]

Answer:

Point C

Step-by-step explanation:

We want to reflect across the x axis

That means the y coordinate changes sign

Z = ( 5 1/2 , 3)

Z' = ( 5 1/2 , -3)

That is point C

8 0
3 years ago
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