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zavuch27 [327]
3 years ago
8

Cos 0=9/15 find tan 0

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

I HAVE NO CLUE BUT HAVE A NICE DAY....

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Round each number to the nearest tenth. What is the best estimate for the answer to 47.82 74.31?
natima [27]

i think that you are multiplying them so the answer is 3553.5

and if your adding it would be 122.1

7 0
3 years ago
Please help!!! Please helpppp!!!!?? PLEASEE I DONT WANNA FAIL I WILL MAKE BRAINLIEST <3
FromTheMoon [43]

Answer:

Triangle Sum Theory

Step-by-step explanation:

You add all the angles to get 180

4 0
3 years ago
Read 2 more answers
Original price: $48; Markup: 12.5%
bogdanovich [222]

Answer:

6.86

Step-by-step explanation:

8 0
3 years ago
I need help with this
Flauer [41]
The given angles are complementary, therefore:

(5r + 5) + (8r -6) = 90°

13r - 1 = 90
13r - 1 + 1 = 90 + 1
13r = 91

13r/13 = 91/13

r = 7
6 0
3 years ago
In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN
Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

      =6²+8²

     = 36 + 64

→AB²  =100

→AB²  =10²

 →AB  =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}

\frac{Ar(ACB)}{Ar(MNC)}=4

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

\frac{24}{Ar(MNC)}=4

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

4 0
3 years ago
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