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Shalnov [3]
3 years ago
9

Help quick!!!! I’m stuck on this

Mathematics
1 answer:
irinina [24]3 years ago
5 0

Answer:

A= pi r(r+h2+r2)

Step-by-step explanation:

Multiply the radius by pi, then set that aside for a bit.

Square the height and the radius as well, then add those together. This is how it would look:

3.14 x 4 = 12.56

7 x 7 = 49  ;   4 x 4 = 16   ;    16 + 49 + 4 = 69   ;   69 x 12.56

I think this is the answer. Can't say I'm 100% sure, though.

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1+4.25n+3/2p-3+(x2p)+5/4n
Pavel [41]

Answer:

1+11/2n+3p^2x

6 0
3 years ago
Shelly sells cars, and she has to sell 50 cars per month t get a bonus. If Shelly sold 28% of the number of cars needed to get a
andrew-mc [135]

Answer: 14

Step-by-step explanation:

28% of 50

3 0
3 years ago
Read 2 more answers
If f(1) = 2 and f (n) = f(n-1) +5 then find the value of f (6)
Nutka1998 [239]

Answer:

f (6) + 1

Step-by-step explanation:

light work I hope this hleps

5 0
3 years ago
Solve for x<br><br> THANK YOU
Anestetic [448]

Answer:

x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}

Step-by-step explanation:

\textsf{Given equation}:

\dfrac{2}{3}x+\dfrac{3x}{x}=\dfrac{4x}{2}(3x+6)

\textsf{Cancel the common factor } x \textsf{ in }\dfrac{3x}{x}:

\implies \dfrac{2}{3}x+3=\dfrac{4x}{2}(3x+6)

\textsf{Simplify }\dfrac{4x}{2}\textsf{ by dividing the numbers}:

\implies \dfrac{2}{3}x+3=2x(3x+6)

\textsf{Apply the distributive law}\quad \:a\left(b+c\right)=ab+ac:

\implies \dfrac{2}{3}x+3=6x^2+12x

\textsf{Multiply both sides by 3 to cancel the denominator of }\dfrac{2}{3}:

\implies \dfrac{2}{3}x\cdot 3+3\cdot 3=6x^2\cdot 3+12x \cdot 3

\implies 2x+9=18x^2+36x

\textsf{Switch sides}:

\implies 18x^2+36x=2x+9

\textsf{Subtract }2x \textsf{ from both sides}:

\implies 18x^2+36x-2x=2x+9-2x

\implies 18x^2+34x=9

\textsf{Subtract 9 from both sides}:

\implies 18x^2+34x-9=9-9

\implies 18x^2+34x-9=0

Solve using the <u>Quadratic Formula:</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Define the variables:

\implies a=18, \quad b=34, \quad c=-9

Substitute the defined variables into the quadratic formula and solve for x:

\implies x=\dfrac{-34 \pm \sqrt{34^2-4(18)(-9)} }{2(18)}

\implies x=\dfrac{-34 \pm \sqrt{1156+648} }{36}

\implies x=\dfrac{-34 \pm \sqrt{1804} }{36}

\implies x=\dfrac{-34 \pm \sqrt{4 \cdot 451} }{36}

\implies x=\dfrac{-34 \pm \sqrt{4}\sqrt{451} }{36}

\implies x=\dfrac{-34 \pm 2\sqrt{451} }{36}

\implies x=\dfrac{-17 \pm \sqrt{451} }{18}

Therefore, the solutions to the given equation are:

x=\dfrac{-17+ \sqrt{451} }{18}, \quad x=\dfrac{-17- \sqrt{451} }{18}

Learn more about the Quadratic Formula here:

brainly.com/question/28105589

brainly.com/question/23700639

3 0
2 years ago
Read 2 more answers
What is the area in square meters of the trapezoid below​
Rina8888 [55]

Given:

Bases of the trapezoid are 5.2 m and 14.6 m.

The height of the trapezoid is 7 m.

To find:

The area of the trapezoid.

Solution:

The area of a trapezoid is:

A=\dfrac{a+b}{2}\times h

Where, a,b are bases and h is the height of the trapezoid.

Putting a=5.2,b=14.6,h=7 in the above formula, we get

A=\dfrac{5.2+14.6}{2}\times 7

A=\dfrac{19.8}{2}\times 7

A=9.9\times 7

A=69.3

Therefore, the area of the trapezoid is 69.3 square meters.

3 0
3 years ago
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