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3 years ago

Find the mean and the median of this data set: 8, 6, 6, 3, 55, 7, 5, 2. The mean is and the median is .

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer:

Mean: 11.5 Median: 6

Step-by-step explanation:

For the mean find the average by adding all of the numbers up and dividing by the number of numbers in the set.

For the median arrange the numbers in order of least to greatest then find the middle number if there is two add them together and divide by two.

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Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc

nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

10 word errors.

This means that $n = 10$

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

$E(Y) = np = 10*0.7 = 7$

The mean number of errors caught is 7.

What is the mean number of errors missed?

$E(X) = np = 10*0.3 = 3$

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

$\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491$

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491$

The standard deviation of the number of errors missed is 1.4491.

6 0

3 years ago

muminat

Answer:

y = 3x + 3

Step-by-step explanation:

when you check, only that equation delivers the correct x and y pairs.

x = 0, => y = 3×0 + 3 = 3

x = 1, y = 3×1 + 3 = 3+3 = 6

x = 2, y = 3×2 + 3 = 6 + 3 = 9

x = 3, y = 3×3 + 3 = 9 + 3 = 12

it all fits.

6 0

2 years ago

Quiz 2 Problem A big ship drops its anchor. The variable ll l l models the anchor's elevation (in meters) relative to the water'

alexandr1967 [171]

Answer:

Initial height of the anchor is 75 meters.

Step-by-step explanation:

We are given the following in the question:

$l(t)=-2.4t+75$

where, I is the anchor's elevation in meter after t seconds dropped from the ship.

We have to find the initial height of anchor that is we have to put t = 0 in the equation.

Putting t = 0, we get,

$l(0)=-2.4(0)+75 = 75$

Thus, initial height of the anchor is 75 meters.

3 0

3 years ago

Read 2 more answers

The table shows the number of miles each person ran this week who ran more miles by te end of the week How many More?

Tasya [4]

To calculate who ran more, you add up the total miles
Pat = 2.75+3+2.5 = 8.25
Toby = 2+2.25+3.5 = 7.75
Now subtract to see who ran more
Pat ran 0.5 miles more than Toby.

Hope this helps

5 0

3 years ago

(6b+9)–(6b+5) . . . . . . . .

fiasKO [112]

Answer:

4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers