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Kitty [74]
3 years ago
11

Plss help i dont understand :(

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0
I believe it’s c I’m 90% sure hope u get 100%
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Could someone please help with these two questions (I WILL MARK BRAINLAST)
dmitriy555 [2]

Answer:

1. b

2. -16

Step-by-step explanation:

1. -1+2 is equal to 1 so it works

You plug in each of the coordinates x and y variables on the graph and find one that satisfies the equation.

2. -(-4)(-5) is -20

-(-4) is = 4

-20+4 is -16

8 0
3 years ago
What is the answer to ...
adelina 88 [10]

Answer:

corresponding

Step-by-step explanation:

corresponding angles are equal

7 0
3 years ago
4. Each morning you do a combination of aerobics, which burns about 12 calories per
nirvana33 [79]

22 minutes is spent doing aerobics and 38 minutes doing stretching

Let x represent the amount of time spent doing aerobics, Let y represent the amount of time spent doing stretching.

Since the goal is to do a 60-minute workout, hence:

x + y = 60     (1)

Also, 416 calories needs to be burnt hence:

12x + 4y = 416    (2)

We need to solve equation 1 and 2 simultaneously; multiply equation 1 by 4 and subtract the result from equation 2, hence:

8x = 176

x = 22 minutes

Put x = 22 in (1)

22 + y = 60

y = 38 minutes

Therefore 22 minutes is spent doing aerobics and 38 minutes doing stretching.

Find out more at: brainly.com/question/16763389

4 0
3 years ago
HELP PLEASE!!
Feliz [49]

Answer:

6163.2 years

Step-by-step explanation:

A_t=A_0e^{-kt}

Where

A_t=Amount of C 14 after “t” year

A_0= Initial Amount

t= No. of years

k=constant

In our problem we are given that A_t is 54% that is if A_0=1 , A_t=0.54

Also , k=0.0001

We have to find t=?

Let us substitute these values in the formula

0.54=1* e^{-0.0001t}

Taking log on both sides to the base 10 we get

log 0.54=log e^{-0.0001t}

-0.267606 = -0.0001t*log e

-0.267606 = -0.0001t*0.4342

t=\frac{-0.267606}{-0.0001*0.4342}

t=6163.20

t=6163.20 years

PLEASE MARK BRAINLY

3 0
4 years ago
A variable of a population has a mean of \mu = 150 and a standard deviation of \sigma= 21 .a. The sampling distribution of the s
Natali [406]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
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