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Diano4ka-milaya [45]
3 years ago
14

What is 2.85 centimeters in expanded form?

Mathematics
1 answer:
sattari [20]3 years ago
5 0
The answer for <span>2.85 centimeters in expanded form is </span>2 centimeters+ .85 centimeters= 2.85 centimeters
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Chuy wants to buy a new television. The television costs $1,350. Chuy decides to save the same amount of money each week, for 27
mars1129 [50]

Answer: option C is the correct answer.

Step-by-step explanation:

The television costs $1,350. Chuy decides to save the same amount of money each week, for 27 weeks. After 8 weeks Chuy saved $440. This means that the amount that she saved per week is

440/8 = $55

If she saves $55 in 8 weeks, the number of weeks left is

27 - 8 = 19 week

Amount that she would save in 19 weeks is

19 × 55 = 1045

Total amount saved in 27 weeks is

1045 + 440 = $1485

Therefore, the conclusion that you can make about Chuy's plan is

C. Chuy will save more than he needs and will meet his goal in less than 27 weeks.

3 0
3 years ago
Hello can you please help me out on this question posted picture
Tatiana [17]
For a parabola if
a) Squared term is x
Parabola either opens up or down.
Positive coefficient means upward opening and negative coefficient means downward opening

b) Squared term is y
Parabola either opens right or left
Positive coefficient means rightwards opening and negative coefficient means leftwards opening

In the given question, since the squared term is y and coefficient is negative, the parabola will open towards left.

So correct answer is option B

4 0
3 years ago
Select all the expressions with accurately written descriptions.
Paha777 [63]
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand. 

1. True
2 times y and 6                                                          -------->(2y+6)
the square of the sum of "2 times y and 6"             -------->(2y+6)^2
8 times  "the square of the sum of 2 times y and 6"------> 8(2y+6)^2

2. True
the difference of x and 7                            -------->(x-7)
9 and x                                                         -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x)  (x-7)

3. True
difference of 5 times x and 3   -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2

4. False
The description should be: the product of 7 and the square of x
the product of 7 and x                        -------->(7x)
the square of the product of 7 and x -------->(7x)^2

5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4

6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8                -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and....                ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
5 0
3 years ago
Read 2 more answers
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
Question Number 12, i need help!! It’s geometry.
Anika [276]
X = 13

( x + 4) / 51 = (2x - 7) / 57
585 = 45x
585/45 = 45x/45
x = 13
6 0
3 years ago
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