Ask question

Ask question

All categories

anyanavicka [17]

3 years ago

15

Se compra un auto nuevo por 17900 dólares.El valor del automóvil se deprecia en 12.25% por año.¿cual será el valor del automóvil

al centavo más cercano después de 10
años

1 answer:

jeyben [28]3 years ago

4 0

17,900 x 0.1296 = 2318.05

2318.05 should be subtracted from 17,900 and it should be somewhere around 15,581.95

You might be interested in

What value of x is in the solution set of 2(3x - 1) >equal to 4x - 6

klasskru [66]

Answer:

x»-2

Step-by-step explanation:

$6x - 2 \geqslant 4x - 6 \\ 2x \geqslant - 4 \\ x \geqslant - 2$

5 0

4 years ago

What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6m?

WINSTONCH [101]

Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
<span><span><span>sector area = 9.6944313302 </span> </span> </span>
<span>sector area = 9.7 square meters (rounded)

Source:
http://www.1728.org/radians.htm

</span>

8 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

Two students in the same Spanish class, Perry and Dakota, plan to get together after school

shtirl [24]

Answer:

Dakota=20 perry=25 together= 45

Step-by-step explanation:

First step, remember to keep 5

second step, if they are find keep multiplying until they both meet the same number which is 20, but they both have 20. But Perry will have 25 since he started a day before

3 0

3 years ago

Your boss gave you a raise. Your weekly salary went from $375 to $450. What was your percent raise?

Yuri [45]

<span>1. Find the difference
2. Divide the difference by the original number it went up from.
</span>
450-375 = 75

75/375 = 0.2

You got a 20% raise.

Proof:
375*.2 = 75
375+75 = 450

3 0

3 years ago