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Simora [160]
2 years ago
15

4. The scatterplot shows the height and age of 12 people.

Mathematics
1 answer:
Stels [109]2 years ago
8 0
The answer is C
Hope this help you!!
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Pls help me this is really hard
LekaFEV [45]

Answer:Find the area of square and then circle then take them away

Step-by-step explanation:

7 0
2 years ago
Plz help me solve it the question is below
AlladinOne [14]

Answer:

\frac{1024}{2025}

Step-by-step explanation:

\frac{3}{4}^{-4}  = \frac{1}{\frac{3}{4}^{4}  }

(3/4)^4 = 81/256

1 ÷  81/256 = 256/81

So;

\frac{256}{81} * \frac{4}{9} = \frac{1024}{729}

\frac{1024}{729} / n = \frac{1}{9/25}

\frac{1024}{729n} = \frac{25}{9} \\\\n = \frac{1024 *9 }{25 * 729}  = \frac{1024}{2025}

6 0
3 years ago
Help please geometry !
Leona [35]
If you use the same technique from the first question, you can do:

5x+2=3x+42
2x=40
x=20

For the rest of the questions, please use the same technique if they are vertical because I can't solve all of the questions for you sorry.
4 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
2 years ago
On October 1, Gary’s bank balance was $130. During October, he made two
swat32

Answer:

The first withdraw could be $30 the second could be $45 and the deposit could be $40

Step-by-step explanation:

130-30=100 100-45=55 95-55=40

130-30-45+40=95

8 0
2 years ago
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