Answer:
a) y = 16°C
b) 25°C, 13°C
Step-by-step explanation:
Apply the distributive property<span>.
</span><span>7x−5−(3x)−1(−2)</span><span>
</span>
<span>Simplify.
</span><span>7x−5−3x−1(−2)
</span>Multiply <span>−1</span><span> by </span><span>−2</span><span> to get </span><span>2.</span><span>
</span><span>7x−5−3x+2</span><span>
</span>
Add <span>7x</span><span> and </span><span>−3x</span><span> to get </span><span><span>4x</span>.
</span><span>4x−5+2</span><span>
</span>
Add <span>−5</span><span> and </span>2<span> to get </span><span><span>−3</span>.
</span><span>4x−3
</span><span>4x−3</span>
Answer:
y = 5/2x
y = 35/2
Step-by-step explanation:
direct variation
y = kx
Substitute the values for x and y
15 = k(6)
Divide each side by 6 yo find k
15/6 = k
5/2 = k
The equation is y = 5/2 x
Now we know x =7
y = 5/2(7)
y = 35/2
Answer:
No, it can not be applied.
Step-by-step explanation:
f(x) = 1/x²
f(x) is a polynomial that is not continuous
As,
f(x) = 1/0 is undefines
Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)
Derivative of this function
f'(x) = (1)x^-2
= -2x^(-2-1)
= -2x^(-3)
= -2/x³
= -2/x³
f'(0) = -2/0 is undefined
Thus, mean value theorem can not be applied.
The answer to your question is b. 2
