Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
70
Step-by-step explanation:
60/40Ⅹ50=70
I hope this helps
F(-5) = -5^2 - 2*(-5) - 7 = 25 - (-10) - 7 = 25 + 10 - 7 = 25 + 3 = 28
Answer:
1 + and a half = 1 in a half
Step-by-step explanation:
The numerator in the first fraction is closest to
10, so the fraction is nearest to 1.
The numerator in the second fraction is closest to 3, so the fraction is nearest to one-half.
The value of the expression can be estimated as 1 + one-half = 1 and one-half.
