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Sonja [21]
3 years ago
15

Given the figure below, find the values of x and z. 80° 0 (15x + 40)​

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0
There’s no photo there
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100 POINTS PLEASE HELP ME I BEG 100 POINTS
Marrrta [24]

Answer:

see explanation

Step-by-step explanation:

(1)

Since FE = FG the triangle is isosceles with ∠ E = ∠ G, then

∠ E = \frac{180-106}{2} = \frac{74}{2} = 37°

(2)

Since all 3 sides are congruent then triangle is equilateral with the 3 angles being congruent, 60° each , then

12y = 60 ( divide both sides by 12 )

y = 5

(3)

The 3 angles are congruent then triangle is equilateral with the 3 sides being congruent, then

KL = JL , that is

4t - 8 = 2t + 1 ( subtract 2t from both sides )

2t - 8 = 1 ( add 8 to both sides )

2t = 9 ( divide both sides by 2 )

t = 4.5

(4)

Given ∠ B = ∠ C then triangle is isosceles with 2 legs being congruent , that is

AB = AC

4x + 1 = 9 ( subtract 1 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

Then

perimeter = AB + BC + AC = 4x + 1 + 2x + 3 + 9

                                            = 6x + 13

                                            = 6(2) + 13

                                            = 12 + 13

                                            = 25

7 0
2 years ago
Read 2 more answers
Pls help me math work
Murljashka [212]

Answer:

Area= 105.12 feet squared

7 0
3 years ago
Find two numbers that multiply to 16 and also add to -8
mash [69]

Answer:

-4,-4

Step-by-step explanation:

let the numbers be x and y.

x+y=-8

y=-x-8

xy=16

x(-x-8)=16

-x²-8x=16

x²+8x+16=0

x²+4x+4x+16=0

x(x+4)+4(x+4)=0

(x+4)(x+4)=0

x=-4,-4

5 0
3 years ago
Tony gets paid 7.25 and hour he gets paid 1.5 for anything over 40 hours. tony work 42.5 hours how much does he get paid
Mekhanik [1.2K]
7.25(40) + (7.25 * 1.5) * 2.5 = 290 + 10.875(2.5) =
290 + 27.1875 = 317.1875 rounds to 317.19
6 0
3 years ago
Read 2 more answers
An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feetquadratic equation h = - 16t^2+
Alex17521 [72]

SOLUTION

The object would hit the ground at the root of the equation, that is where h = 0

So we have

\begin{gathered} h=-16t^2+32t+48=0 \\ -16t^2+32t+48=0 \\ 16t^2-32t-48=0 \\ divide\text{ through by 16} \\ t^2-2t-3=0 \end{gathered}

Solving the quadratic equation, we have

\begin{gathered} t^2-3t+t-3=0 \\ t(t-3)+1(t-3)=0 \\ (t-3)(t+1)=0 \\ t=3,\text{ or} \\ t=-1 \end{gathered}

So we ignore -1 as time cannot be negative.

Hence the object hit the ground in 3 seconds

3 0
1 year ago
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