Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
10) 51°
11) 152
Step-by-step explanation:
10) 42 + 9 = 51
11) 45(3.5) + 22(-.25) = 157.5 - 5.5 = 152
Answer:
y=x+20
Step-by-step explanation:
we have to find the slope
y2-y1/x2-x1
3-2/23-22
1/1
y=1x+b
y-22 = 1(x-2) + b
y=x+20
Can someone please help me answer this my grade depends on it!
a. 3 gallons 1 cup
b. 15 cups
