<span>The rectangle with the largest area with a given perimeter will be a square - so the sides will be equal. So we need to find length of side, L, such that 4*L=168.
L = 168/4
L=42.
So the dimensions of the rectangle that maximizes the area with a perimiter of 168 feet are: 42 feet by 24 feet.</span>
There is a one ever other number?
Answer:
a. m DCB =<DAB=120 opposite angle of the parallelogram are equal
again
BP=PD diagonal bisect it
3x+7=-x+17
3x+x=17-7
4x=10
x=10/4=5/2
b. BD =3x+7-x+17=3×5/2+7-5/2+17=2×5/2+24=5+24=29
