n, n + 1, n + 2, n + 3 - four consecutive integers
-142 - the sum
The equation:
n + (n + 1) + (n + 2) + (n + 3) = -142
n + n + 1 + n + 2 + n + 3 = -142
4n + 6 = -142 |subtract 6 from both sides
4n = -148 |divide both sides by 4
n = -37
n + 1 = -37 + 1 = -36
n + 2 = -37 + 2 = -35
n + 3 = -37 + 3 = -34
Answer: -37, -36, -35, -34.
-4x - 11 = 2(x - 3x) + 13
-4x - 11 = 2x - 6x + 13
-4x - 11 = -4x + 13
-4x + 4x = 13 + 11
0 = 24...incorrect......no solutions for this problem
Answer:
D
Step-by-step explanation:
ABCD is the same as JKML
M=D
5+ 2n < 1+ 6n , n= number
Answer:
1. Make a dot plot that has numbers in order from 0 to 8. Plot a dot for each amount of each number that have been recorded.
2.
1. CQ 2. DQ 3. C 4. C 5. DQ
Step-by-step explanation:
