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sammy [17]
3 years ago
15

The value of the surface area of the cylinder is equal to the value of the volume of the cylinder. Find the value of x.

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0
Radius, r = 7.2
Height, h = x

Surface of the cylinder
2*pi*r*x

Volume of the cylinder
pi*r^2*x

2*pi*r*h = pi*r^2*h
2 = r


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Jeffery is playing a game with two spinners below:
Mrrafil [7]

The <em>correct answer</em> is:


{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .


Explanation:


The sample space for rolling these two spinners is:


(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)


This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12


As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

3 0
3 years ago
Read 2 more answers
If you take a number, times by 5 then add 7. You get the same as if you took the number, times by 9 then add 3. What is the numb
Scorpion4ik [409]

Answer:

5_7=2 9_3=6. 5+7=12 9+3=12

Step-by-step explanation:

6 0
3 years ago
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2.283:3<br> What is the answer ?
ehidna [41]

Answer:

0.761

Step-by-step explanation:

first you do 3 divided by 2.2 and get .733 which you round to .7

next you do 3 divided by 2.28 and get .76

last you do 3 divided by 2.283 and get .761

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Write 0.245bar in the form p/q
frozen [14]

Answer:

245/999

Step-by-step explanation:

0.245bar = n

1000 n - n = 245

999n = 245

n = 245/999

6 0
3 years ago
Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)

As \ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0

So, \frac{dy}{dx}>0

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)

As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

6 0
3 years ago
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