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Law Incorporation [45]
3 years ago
11

Jeffery is playing a game with two spinners below:

Mathematics
2 answers:
Anna35 [415]3 years ago
5 0
The possible outcomes for Jeffrey in spinning the two spinner is <span>{3, 4, 5, 6, 7, 8, 9, 10, 11, 12}. The smallest possibility is the the two yellow which is 1 and 2 that results to 3 and the larges possible is 4 and 8 the should be 12. </span>
Mrrafil [7]3 years ago
3 0

The <em>correct answer</em> is:


{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .


Explanation:


The sample space for rolling these two spinners is:


(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)


This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12


As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

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Masja [62]

Answer:

q = ±  \frac{5}{4\sqrt{p} }

Step-by-step explanation:

We are to solve for q in:

16pq² = 25

q² = \frac{25}{16p}

\sqrt{q^2} = ±\sqrt{\frac{25}{16p} } = ± \frac{5}{4\sqrt{p} }

5 0
3 years ago
Need help with math problem please
Zigmanuir [339]
P= -8, 3
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An open box is to contain a volume of 3 cubic meters. Given that the material forthe sides of the box costs 6 per square meter a
bekas [8.4K]

Answer: total cost = 36/w + 36/l + 9lw

Step-by-step explanation:

The formula for determining the volume of the rectangular box is expressed as

Volume = lwh

Where lwh represents the length, width and height of the box respectively.

Since the volume of the box = 3cm³,then

lwh = 3

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Given that the material for the sides of the box costs 6 per square meter, the total cost for the sides is

(2lh × 6) + (2wh × 6)

Substituting h = 3/lw into the above expression, it becomes.

(2l × 3/lw × 6) + (2w× 3/lw × 6)

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Since the material for the bottom costs 9per square meter, the total cost for the bottom is

9 × lw = 9lw

Therefore, the total cost of the box as a function of the length land width is

36/w + 36/l + 9lw

7 0
3 years ago
Whats 100+100+100+100+100/2+234/23*274612+1836-279658.61-2516250-255-12+11+1.1-.09869565
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Step-by-step explanation:

Hope this Helps! :)

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