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xz_007 [3.2K]
3 years ago
11

Use the discriminant to determine the number of solutions. x2 + x = 12

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Answer:

x=4

Step-by-step explanation: So you do 2x plus 1x which is 3x. Then you divide both sides by 3 which leaves you with x=4. Thats your answer. <3

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What is the next 2 numbers in the sequence? <br><br> 343,131413,11131114113
VashaNatasha [74]

Answer:

111113111114111113 and 111111131111111411111113

Step-by-step explanation:

Here we want to know the next two numbers in the sequence.

The key here is that we shall be placing the same number of digit 1 between each of the digits 3 4 3

We went from a single 1 to triple, so the next will be 5 digit 1 and the next will be 7 digit 1

So the next number after the third will be;

111113111114111113

The next number after this will be;

111111131111111411111113

5 0
3 years ago
Explain why P(A|D) and P(D|A) from the table below are not equal. A 4-column table has 3 rows. The first column has entries A, B
dangina [55]

Answer:

P(A|D) and P(D|A) from the table above are not equal because P(A|D) = \frac{2}{10} and P(D|A) = \frac{2}{8}

Step-by-step explanation:

Conditional probability is the probability of one event occurring  with some relationship to one or more other events

.

P(A|D) is called the "Conditional Probability" of A given D

P(D|A) is called the "Conditional Probability" of D given A

The formula for conditional probability of P(A|D) = P(D∩A)/P(D)

The formula for conditional probability of P(D|A) = P(A∩D)/P(A)

The table

               ↓         ↓       ↓

            :  C     :   D    : Total

→ A      :  6     :    2    :   8

→ B      :  1      :    8    :   9

→Total :  7     :    10  :  17

∵ P(A|D) = P(D∩A)/P(D)

∵ P(D∩A) = 2 ⇒ the common of D and A

- P(D) means total of column D

∵ P(D) = 10

∴ P(A|D) = \frac{2}{10}

∵ P(D|A) = P(A∩D)/P(A)

∵ P(A∩D) = 2 ⇒ the common of A and D

- P(A) means total of row A

∵ P(A) = 8

∴ P(D|A) = \frac{2}{8}

∵ P(A|D) = \frac{2}{10}

∵ P(D|A) = \frac{2}{8}

∵  \frac{2}{10} ≠  \frac{2}{8}

∴ P(A|D) and P(D|A) from the table above are not equal

5 0
4 years ago
Read 2 more answers
How do i find the y-intercept for f(x)=|x|-5
wel
The y-intercept for f(x)=|x|-5 is (-5). Just look at the function as slope-intercept form and find the number that is not being multiplied by x. That number will usually be your y-intercept.
8 0
3 years ago
Read 2 more answers
I need help! And I need a reasoning as well
Sindrei [870]

Answer:

A) 3²·3³

E) 3^4·3^1

Step-by-step explanation:

When multiplying numbers with exponents, keep the base the same and add the exponents.

So A and E would equal 3 to the fifth power.

6 0
3 years ago
Read 2 more answers
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions
quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of v_0 and F_2 be the component normal to v_0.

Since, |v_0| = 1,

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, v_0 = \left

From figure,

|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3

We know that the direction of F_1 is opposite of the direction of v_0, so we have

$F_1 = -5\sqrt3 v_0$

    $=-5\sqrt3 \left$

    $= \left$

The unit vector in the direction normal to the plane, v_1 has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5

∴  F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>

                   $=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

           $= = F$

3 0
3 years ago
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