Question

Solve for x, where x is a real number.

Answer 1

Hello!

First of all, let's undo the square roots by squaring both sides.

6x+2=9x-8

We subtract 9x from both sides.

-3x+2=-8

We subtract 2 from both sides.

-3x= -10

We divide both sides by -3.

x=10/3

I hope this helps!

Answer 2

$\sqrt{6x+2}=\sqrt{9x-8}\qquad \left(x\geq-\dfrac{1}{3} \wedge x\geq \dfrac{8}{9}\implies x\geq \dfrac{8}{9}\right)\\\\ 6x+2=9x-8\\\\ 3x=10\\\\ x=\dfrac{10}{3}$