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borishaifa [10]
2 years ago
6

Solve for x, where x is a real number.

Mathematics
2 answers:
Alex787 [66]2 years ago
7 0

Hello!

First of all, let's undo the square roots by squaring both sides.

6x+2=9x-8

We subtract 9x from both sides.

-3x+2=-8

We subtract 2 from both sides.

-3x= -10

We divide both sides by -3.

x=10/3

I hope this helps!

o-na [289]2 years ago
5 0

\sqrt{6x+2}=\sqrt{9x-8}\qquad \left(x\geq-\dfrac{1}{3} \wedge x\geq \dfrac{8}{9}\implies x\geq \dfrac{8}{9}\right)\\\\ 6x+2=9x-8\\\\ 3x=10\\\\ x=\dfrac{10}{3}

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I need help please. Thanks
Agata [3.3K]

Given:

m∠APD = (7x + 1)°

m∠DPC = 90°

m∠CPB = (9x - 7)°

To find:

The measure of arc ACD.

Solution:

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠APD + m∠DPC + m∠CPB = 180°

7x° + 1° + 90° + 9x° - 7° = 180°

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Subtract 84° from both sides.

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Divide by 16° on both sides.

x = 6

m∠APB = 180°

m∠BPD = (9x - 7)° + 90°

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             = 47° + 90°

m∠BPD = 137°

m∠APD = m∠APB + m∠BPD

             = 180° + 137°

             = 317°

<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>

m(ar ACD) = m∠APD

m(ar ACD) = 317°

The arc measure of ACD is 317°.

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3 years ago
I am having trouble figuring out this problem. I believe the answer is (0,7) but I am not sure.
AleksandrR [38]

It is (0,7).

7(cos(pi/2)+isin(pi/2))

7i which is (0, 7)

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3 years ago
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