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3 years ago

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Ahmed is working at a restaurant . His boss pays him $15.50 per tour and promises a raise of $1.25 per hour every 6 months. Whic

h sequence describes Ahmeds expected hourly wages, in dollars, starting with his current wage
A. 15.50, 31.00, 46.50, 62.00,...
B. 15.50, 16.75, 18.00, 19.25,...
C. 1.25, 2.50, 3.75, 5.00,...
D. 6.00, 7.25, 8.50, 9.75,...

1 answer:

grandymaker [24]3 years ago

3 0

No se need puntos idk sorry jajjajaydyajjshdhdgeyyetegegdvdbds

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Toby wants to buy 2 concert tickets that cost $19 each. His makes $4.75 an hour while he mows lawns. How many hours will he need

nikitadnepr [17]

Cost of a ticket = $19
So, cost of two tickets = 19 * 2 = $38

Now, he makes, $4.75 in an hour.
Let, the number of hours for that much money = x

It would be: 4.75x = 38
x = 38 / 4.75
x = 8 hours

In short, Your Answer would be 8 hours

Hope this helps!

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3 years ago

6 times the number of waiters at a restaurant was 6 less than the number of

morpeh [17]

Answer:

12

Step-by-step explanation:

6x3-6=12

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3 years ago

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Find the area of the composite figure.

Minchanka [31]

Answer:

132 square feet

Step-by-step explanation:

The formula for the area of a triangle is 1/2 * b * h. B stands for base and h stands for height. 1/2 multiplied by the base, 10, is 5. We then multiply 5 by 12 which is 60. Let's look at the rectangle now. The area of a rectangle is length by width. The length is 12ft and the width is 6ft. 12 * 6 = 72. 72+60=132 square feet.

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2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

Divide 800ml into ratio 3:7

Black_prince [1.1K]

Simply take the numerator (3) and denominator (7) and add them together.

3+7 = 10, which means that the ratio will provide parts that are in multiples of 10 depending on the total

so take 10x = 800

x = 80.

Then multiply this by the numerator and denominator

3*80/7*80 = 240/560.

7 0

3 years ago