Divide 800ml into ratio 3:7

1 answer:

7 0

Simply take the numerator (3) and denominator (7) and add them together.

3+7 = 10, which means that the ratio will provide parts that are in multiples of 10 depending on the total

so take 10x = 800

x = 80.

Then multiply this by the numerator and denominator

3*80/7*80 = 240/560.

You might be interested in

Did i do 1 correctly

Olin [163]

Step-by-step explanation:

3 : x = -7.5

5 : x = -10

6 : x = 12

remaining answers are correct

7 0

2 years ago

a recent survey shows that 16% of college students have dogs and 38% have an HBO subscription. assuming these two events are ind

Nataly_w [17]

Answer: $0.939\ or\ 93.9\%$

Step-by-step explanation:

Given

Survey shows that 16% of college students have dogs and 38% have HBO subscription

Probability that a random person have both is

$\Rightarrow P_o=0.16\times 0.38\quad [\text{As both events are independent}]\\\Rightarrow P_o=0.0608$

The probability that the random person has neither of the two is

$\Rightarrow P=1-P_o\\\Rightarrow P=1-0.0608\\\Rightarrow P=0.939$

3 0

3 years ago

Is the following situation represented by a positive integer, a negative integer, or zero? Sami was sick last week and lost 2 po

Paha777 [63]

Answer:

i hope find help but i dont know

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Determine the arithmetic sequence if the fourth term is negative six and the eleventh term is negative thirty four

ICE Princess25 [194]

An arithmetic sequence takes the form

$a_n=a_{n-1}+d$

where $d$ is the common difference between terms. You can solve for $a_n$ in terms of any of the previous terms of the sequence:

$a_n=a_{n-1}+d\implies~a_n=a_{n-2}+2d\implies~a_n=a_{n-3}+3d\implies\cdots\implies~a_n=a_{n-k}+kd$

for some integer $1\le k\le n-1$

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term $a_1$

$a_n=a_1+(n-1)d$

Given that the 4th term is $a_4=-6$ and the 11th term is $a_{11}=-34$ , you have the following system of equations.

$\begin{cases}-6=a_1+(4-1)d\\-34=a_1+(11-1)d\end{cases}$

Solving this system for the two unknowns yields $a_1=6$ and $d=-4$ .

So, the sequence is given explicitly by

$a_n=6+(n-1)(-4)=-4n+5$