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exis [7]
3 years ago
10

Write the rational number 0.3 in the form ab , where a and b are integers.

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Answer: 3/10

Step-by-step explanation:

Given a decimal number 0.3

To Write the rational number 0.3 in the form ab , where a and b are integers, take it to be :

0.3 /1

Multiply the numerator and the denominator by 10

0.3/1 × 10/10 = 3/10

Therefore, a = 3 and b = 10

the rational number 0.3 in the form ab , where a and b are integers is

3/10

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Answer:

1.2

Step-by-step explanation:

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A restaurant uses 5 Gallons of milk each day How many 1-Quart containers of milk does the restaurant use each day
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The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

2=a(0)^2+b(0)+c

c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

substitute equation A in equation B

0=4(b-2)-2b+2

solve for b

0=4b-8-2b+2

2b=6

b=3

Find the value of a

a=3-2=1

therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

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3 years ago
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sergiy2304 [10]
What do you mean by in words?
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3 years ago
6x squared plus 12x plus 13 equals 2x squared plus 4
Andrews [41]
12x^2+12x+3=2x^2+4\\\\12x^2-2x^2+12x+3-4=0\\\\10x^2+12x-1=0\\\\a=10;\ b=12;\ c=-1\\\\\Delta=12^2-4\cdot10\cdot(-1)=144+40=184\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{184}=\sqrt{4\cdot46}=2\sqrt{46}\\\\x_1=\frac{-12-2\sqrt{46}}{2\cdot10}=\frac{-6-\sqrt{46}}{10};\ x_2=\frac{-12+2\sqrt{46}}{2\cdot10}=\frac{-6+\sqrt{46}}{10}
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