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ddd [48]
2 years ago
5

Show full workout Change the following bases to decimala. 101011b. 2373​

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
4 0
B I think if I’m wrong I sooooo sorry
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Alison has 3 containers with 25 crayons in each.She also has 4 boxes of markers with 12 markers in each box. She gives 10 crayon
svet-max [94.6K]
3 x 25 = 75
4 x 12 = 48
75 - 10 = 65
65 + 48 = 113
Answer: 113 markers and crayons or 65 crayons and 48 markers
6 0
3 years ago
Annita, Gary, and Tara all run races. Annita has 7 less than 4 times the number of race medals as Tara. Gary has 13 more than 2
harkovskaia [24]

Answer:

4 t - 7  = 2 t+ 13  is the required equation.

The number of race medals Tara has is t = 20 medals.

Step-by-step explanation:

Let the number of medals Tara has = t medals

So, the number of medal Anita has  = 4( Medals of Tara) - 7

= 4t - 7

And the number of medals Gary has = 2 times (Medals of Tara) + 13

= 2(t)  + 13  = 2t + 13

Now, Annita and Gary has same number of medals.

⇒  4t - 7  = 2t+ 13

or, 4t - 2t  = 7 + 13

⇒ 2t  = 20

⇒ t = 20/2 = 10

or t = 10

Hence, the number of race medals Tara has is t = 20 medals

6 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
2 years ago
14. Which of the following is not a true statement about the scatter plot above?
harina [27]

Answer:

Step-by-step explanation:

5 0
2 years ago
9.<br> Kyle ran 150 feet in 15 seconds, how many hours would it take him to<br> run 30 miles?
PtichkaEL [24]
She runs 30 miles in 3 seconds
8 0
2 years ago
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