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mario62 [17]
3 years ago
15

What is the inverse of the linear equation y=2x+4?

Mathematics
2 answers:
matrenka [14]3 years ago
6 0
The inverse is an equation that shows 'x' in terms of 'y'.
The new equation will say
                                          x = something .

We just have to take the given equation and solve it for 'x'.

                                      y          =  2x + 4
Subtract  4
from each side:               y - 4     =  2x

Divide each side by  2 :    (y-4)/2 = x
Stella [2.4K]3 years ago
5 0
To find the inverse of an equation simply switch the X and y coordinates and solve for the new Y coordinate.

Y = 2x + 4
X = 2y + 4
X - 4 = 2y
X-4/2 = 2y/2

Y = X - 4/2.
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Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?
matrenka [14]

Answer: C. The graph of f(x)= x2 is shifted down 36 units

Step-by-step explanation:

6 0
3 years ago
in ABC the measure of angle A is 2x+3 the measure of angle B is 4x+2 the measure of angle C is 2x-1 what are the measures of the
Virty [35]


IN A triangle, sum of all angles = 180 degrees

2x + 3 + 4x+2 + 2x -1 = 180

8x +4  = 180

8x = 176

x = 176 /8 = 22 degrees

the angles are A = 2(22)+3 = 44+3 = 47 DEGREES

B = 4(22)+2 = 88 + 2 = 90 DEGREES

C = 2(22) -1 44-1 = 43 DEGREES

7 0
3 years ago
Read 2 more answers
How many complex zeros does the polynomial function have? <br><br> F(x)=2x^4 +5x^3 - x^2 +6x-1
klio [65]

Answer:

Two complex roots.

Step-by-step explanation:

F(x)=2x^4 +5x^3 - x^2 +6x-1

is a polynomial in x of degree 4.

Hence F(x) has 4 roots.  There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.

Use remainder theorem to find the roots of the polynomial.

F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0

There is a change of sign in F from 0 to 1

Thus there is a real root between 0 and 1.

Similarly by trial and error let us find other real root.

F(-3) = -1 and F(-4) = 94

SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.

Other two roots are complex roots since no other place F changes its sign

7 0
3 years ago
50 POINTS + BRAINLIEST TO CORRECT ANSWER!! TRIG/GEO
WINSTONCH [101]

Option C:

We can find the value of PR using law of cosines.

Solution:

Given data:

∠Q = 18°, r = 9.5, p = 6.0

To find which length could be find in the triangle:

Law of cosines:

a^{2}=b^{2}+c^{2}-2 b c \cos A

Substitute a = q, b = r, c = p and A = Q

q^{2}=r^{2}+p^{2}-2 r p \cos Q

If we substitute the values given, we can find q.

q = PR

PR^{2}=r^{2}+p^{2}-2 r p \cos Q

Hence we can find the value of PR using law of cosines.

Option C is the correct answer.

3 0
3 years ago
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Help me with this Geometry question please
Mnenie [13.5K]

Answer:

not 100% sure but answer should be 59

Step-by-step explanation:

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4 0
3 years ago
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