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strojnjashka [21]
3 years ago
6

Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller

sphere is 5 cm and that of the larger sphere is 12 cm. The electric field at the surface of the larger sphere is 280 kV/m. Find the surface charge density on each sphere.
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

1.02*10^-5 C/m²

Explanation:

Given that

Radius of the smaller sphere, r = 0.05 m

Radius of the larger sphere, R = 0.12 m

Electric field, E = 2*10^5 V/m

Formula for the electric field is

E = Q/(4πεR²)

this then means that the surface charge density of the larger sphere is

Q/4πR² = Eε = 1.77*10^-6 C/m²

and

Q = 4πεER² = 3.203*10^-7 C

is the charge on the large sphere, which is the same as the charge on the small sphere since they are connected by the wire

so the surface charge density of the smaller sphere is

Q/4πr² = 4πεER²/4πr²

Q = εER²/r²

Q = 1.02*10^-5 C/m²

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Answer:

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Explanation:

To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.

P * v = R * T

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T = temperature [K]

<u>For the initial state</u>

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P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)

T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)

Therefore we can calculate the specific volume:

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v1 = 0.29 [m^3/kg]

As there are no leaks, the mass and volume are conserved, so the volume in the initial state is equal to the volume in the final state.

V2 = 0.29 [m^3/kg], with this volume and the new temperature, we can calculate the new pressure.

T2 = 43 + 273 = 316 [K]

P2 = R*T2 / V2

P2 = (0.287 * 316) / 0.29

P2 = 312.73 [kPa]

Now calculating the manometric pressure

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iVinArrow [24]

Answer:

<em>The magnitude of the magnetic field will act in a direction towards me.</em>

<em></em>

Explanation:

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Answer:

Explanation:

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