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frez [133]
3 years ago
15

Would an astronauts mass change as she traveled from planet to planet? Explain.

Physics
1 answer:
Lunna [17]3 years ago
7 0
No, it's mass remains the same. It's attraction to the planets center AKA gravity changes.
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When wile coyote is launched his velocity is 20 m/s. As a slightly underweight 10kg coyote, how far would the 400 N/m spring hav
Deffense [45]

Answer:

E = 1/2 m v^2 = 1/2 k x^2     equating KE of coyote and spring

x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m

x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2

x = 3.16 m

3 0
3 years ago
The lens of the eye focuses light on the
pav-90 [236]

Answer

Cornea

Explanation:

The lens is composed of transparent, flexible tissue and is located directly behind the iris and the pupil. It is the second part of your eye, after the cornea, that helps to focus light and images on your retina.

4 0
4 years ago
Read 2 more answers
What is the magnitude of g at a height above Earth’s surface where free- fall acceleration equals 6.5 m/s2 ?
satela [25.4K]
Well, the "magnitude of g" in a place is always described as the
free-fall acceleration there.  So your ' 6.5 m/s² ' is the answer to
the question.
6 0
4 years ago
Diesel engines make use of a _______ to add additional combustion chamber heat for cold weather starting.
Andrews [41]
Diesel engines are relatively cheaper than most other commercial engines. Combustion in the engine is started by ignition of high temperatures of the fuel. The best answer is B. glow plug. The glow plug is the device that aids this combustion-ignition process most especially for cold weather. Of course, heat is needed to start up the engine. The glow plug is this heating element as aid in starting up.
6 0
3 years ago
Calculate the electric charge of the glass ball
-Dominant- [34]

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

4 0
3 years ago
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