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zalisa [80]
3 years ago
12

Which statements describe elliptical galaxies? *Select the two correct answers.*

Physics
2 answers:
Alecsey [184]3 years ago
6 0

Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.

The <u>two correct statements</u> that describe elliptical galaxies are:

B. They are the most common galaxy type.

C. They typically contain very little gas and dust.

  • Elliptical galaxies are galaxies where you will find little or no gas and dust. The galaxies that are numerous in number are the elliptical galaxies.

  • In the elliptical galaxy, you can't find any <u>spiral component </u>in it.

Therefore, from the above explanation, we can see that <u>option B and C is the correct option.</u>

To learn more, visit the link below:

brainly.com/question/13645005

umka2103 [35]3 years ago
5 0

The statements which describes elliptical galaxies are Choice B and Choice C:

  • They are the most common galaxy type.

  • They typically contain very little gas and dust.

  • Elliptical galaxies are the most abundant type of galaxies found in the universe although because of their age and dim qualities, they're frequently outshone by younger, brighter collections of stars

  • Elliptical galaxies are characterized by the presence of less gas and dust and as such, new shiny stars are not born and the dim nature of elliptical galaxies can be attributed to this.

Ultimately, elliptical galaxies are the oldest and are the most common galaxy type and they typically contain very little gas and dust.

Read more:

brainly.com/question/14459434

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timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

F_n = \frac{mv^2}{r}

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Here,

Normal reaction of the ring is N and velocity of the ring is v

N+mgcos\theta = \frac{mv^2}{r}

N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})

N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}

N = 1.374lb

PART B) Acceleration

F_t = ma_t

-mgsin\theta = ma_t

-W sin\theta = \frac{W}{g} a_t

-2Sin30\° = (\frac{2}{32.2})a_t

a_T = -16.10ft/s^2

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0
3 years ago
Stellar nurseries, such as the orion nebula, contain hundreds or more fragmenting and contracting regions, as well as many proto
Natasha_Volkova [10]

The hydrogen fusion process will begin after the protostar reaches a temperature of 10 million degrees kelvin, and it will then turn into a stable star.

<h3>How does a protostar become a stable star?</h3>

The interstellar medium can sometimes be gathered into a large nebula, which is a cloud of gas and dust. A nebula can span a number of light years. These nebulae are where gas and dust can combine to produce stars. Until a star can combine hydrogen into helium, it cannot be considered a star. They are referred to as protostars before then. As gravity starts to gather the gases into a ball, a protostar is created. Accrution is the term for this procedure.

Gravitational energy starts to heat the gasses as gravity draws them into the ball's core, which causes the gasses to radiate radiation. Radiation initially just dissipates into space. However, much of the radiation is retained inside the protostar as it draws in stuff and becomes denser, which causes the protostar to heat up even more quickly.

The hydrogen fusion process will begin after the protostar reaches a temperature of 10 million degrees kelvin, and it will then turn into a star.

Learn more about a protostar here:

brainly.com/question/12534975

#SPJ4

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All organisms have adaptations. The list below describes how different adaptations might affect different species.
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I give a ball a push on an acclivity. The "start velocity" is on 7m/s. The time it took the ball to get back to me was 10 second
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Answer:

7÷10

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