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sweet-ann [11.9K]
3 years ago
14

A book shelf holds twenty books. Eleven are hard- covered, nine of the books are nonfiction, and four of the nonfiction books ar

e hard-covered, as shown in the Venn diagram. Let event H be a hard-covered book and let event N be a nonfiction book
Mathematics
2 answers:
ololo11 [35]3 years ago
7 0

Answer:

1) Find the probability that a chosen book is nonfiction and hard-covered. P(N ∩ H) = 4/20

2) Find the probability that a chosen book is hard-covered. P(H) =  11/20

3) Calculate the conditional probability. = 4/11

---------------------------------------------------------------------------------------------

1.) 4/20

2.) 11/20

3.) 4/11

sasho [114]3 years ago
7 0

Answer: 4/20

11/20

4/11

Step-by-step explanation:

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tester [92]

Answer:

64y² - 81

Step-by-step explanation:

(8y +9)(8y - 9)

64y² - 72y + 72y - 81

64y² - 81

6 0
3 years ago
Read 2 more answers
Shobo's mother's present age is six times Shobo's present age. Shobo's age five
il63 [147K]

Answer:

Step-by-step explanation:

Shobo's age = x years

His mother's age = 6 times of

Shobo's age

= 6x years

Five years from now

________________

Shobo's age = ( x + 5 ) years

According to the problem given,

x + 5 = one by third of his mother's

present age

x + 5 = 6x / 3

x + 5 = 2x

5 = 2x - x

5 = x

Therefore ,

Shobo's present age = x = 5 years

His mother's age = 6x

= 6 × 5

= 30 years

4 0
3 years ago
SOLVE: 18x+103x-3x<br> ill give brainliest
JulijaS [17]

Answer:

118x

Step-by-step explanation: hopes this helps

4 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
(2a+b)^2÷(3b-1) when a= -2 and b=5
WINSTONCH [101]
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

 | 1 | 5
- | | 1
 | 1 | 4:
(5 - 2×2)^2/14

2 (-2) = -4:
(-4 + 5)^2/14

5 - 4 = 1:
1^2/14

1^2 = 1:

Answer: 1/14
6 0
3 years ago
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