Arie ran an equal number of miles each day for 12 days. He ran 60 miles in total.
2 answers:
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Answer:
51.625
Step-by-step explanation:
Given a unsigned binary number, to calculate the unsigned decimal:
first, starting at dot, you list the positive powers of 2 from right to left beginning in that is equal to “1”. Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers:
.
Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in that is equal
= 0.5. so you get:
Now, join two parts and you get:
1 1 0 0 1 1. 1 0 1
Then, you write the equivalent of each of the power below from corresponding binary digit, like that:
1 1 0 0 1 1. 1 0 1
| | | | | | | | |
32 16 8 4 2 1 0.5 0.25 0.125
Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:
1 1 0 0 1 1. 1 0 1
| | | | | | | | |
32 16 8 4 2 1 0.5 0.25 0.125
_______________________________________
32 16 0 0 2 1 0.5 0 0.125
32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625
So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625
Answer:
Where 0 < x < 3
The location of the local minimum, is (2, 0)
The location of the local maximum is at (0, 16)
Step-by-step explanation:
The given function is f(x) = (x + 2)⁴
The range of the minimum = 0 < x < 3
At a local minimum/maximum values, we have;
∴ (-x + 2)³ = 0
x = 2
When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2
We have, f(2) = (-2 + 2)⁴ = 0
The location of the local minimum, is (2, 0)
Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3
When x = 0, -x + 2 = 0 + 2 = 2
Similarly, we have;
-x + 2 = 1, when x = 1
-x + 2 = 0, when x = 2
-x + 2 = -1, when x = 3
Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16
The location of the local maximum is at (0, 16).