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pickupchik [31]
3 years ago
12

Pls help ????????????

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0

Answer:

let the missing values be a , b , c ,d and e

So the mean of these values is $ 2225

<em>(a + b + c + d + e + 1900 + 2300 + 3000)/8 = 2225</em>

<em>a + b + c + d + e + 7200 = 2225*8</em>

<em>a + b + c + d + e = 17800 - 7200</em>

a + b + c + d + e = 10600 -------------------- let this be our first equation

Since the range is 3000 and the data is already in increasing order:

3000 - a = 2100

a = $ 900 --------- one down, 4 to go

Now lets get another equation through Median:

So the median value is 2450, since median is the middle value when the given set is written in increasing or decreasing order

since we are already given the increasing order of the numbers, we will make use of that

So, since there is no middle number since there are even amount of numbers, the average of the 2 mid numbers will be the Median

so, (2300 + c)/2 =  2450

2300 + c = 4900

c = $ 2600 ---------------------- two down, 3 to go

Now we will try to get another equation through mode

We are given that the mode of the numbers is 2900

we will take some help from the first equation for this part

a + b + c + d + e = 10600

900 + 2600 + b + d + e = 10600

b + d + e = 10600 - 3500

b + d + e = 7100

Since the mode is 2900, lets check if b + d + e = 3 (2900) since that would mean that 2900 is repeated 3 times

b + d + e = 2.45(2900)

since b + d + e is 2.45 times 2900 and 2900 is the most repeated number,

we can say that 2 of the 3 values is 2900

so,

2900 + 2900 + b = 7100

e = 7100 - 5800

e = $ 1300

so the complete list is: 900 , 1300 , 1900 , 2300 , 2600 , 2900 , 2900 , 3000

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