3 years ago

75% of Grant’s coin collection is quarters. If Grant has 200 coins in his collection, how many are quarters?

Mathematics

1 answer:

Eddi Din [679]3 years ago

5 0

Answer:

150 of Grant`s coins are quarters. i hope this helped

You might be interested in

Can you give a reason of who is correct and why

andreyandreev [35.5K]

Answer:

What is the question

Step-by-step explanation:

8 0

3 years ago

Solve the system by graphing.<br> y = -x + 5 <br><br> y = x + 1

Sergio039 [100]

Step-by-step explanation:

the answer from the graph is:

(2 , 3)

7 0

3 years ago

Find the equation of the circle whose center is at (4, 5) and that contains (13, −1).

zepelin [54]

The equation of circle is
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117

3 0

3 years ago

Solve the Differential equation 2(y-4x^2) dx + x dy = 0

padilas [110]

Assume a solution of the form $\Psi(x,y)=C$ . Taking the differential of both sides would give the ODE

$\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0$

where $\Psi_x=2y-8x^2$ and $\Psi_y=x$ . The ODE is exact if $\Psi_{xy}=\Psi_{yx}$ . We have

$\Psi_{xy}=(2y-8x^2)_y=2$

$\Psi_{yx}=(x)_x=1$

so the ODE is not exact. However, multiplying both sides by $x$ gives

$(2xy-8x^3)\,\mathrm dx+x^2\,\mathrm dy=0$

and now

$(x\Psi_x)_y=(2xy-8x^3)_y=2x$

$(x\Psi_y)_x=(x^2)_x=2x$

so the ODE is now exact.

Now,

$\Psi_x=2xy-8x^3\implies \Psi(x,y)=x^2y-2x^4+f(y)$

$\Psi_y=x^2=x^2+f_y\implies f_y=0\implies f(y)=C$

So the ODE has solution

$\Psi(x,y)=x^2y-2x^4+C=C$

or simply

$\boxed{x^2y-2x^4=C}$

3 0

4 years ago

Please help and thank you

vovangra [49]

D) 38 feet hope this helped just in time

8 0

4 years ago