Please Hurry!!!!!! I really need help

Sergio runs 2 1/4 miles in 30 minutes. Write the ratio in fractional form and determine Sergio's speed in miles per hour.

klasskru [66]

$\dfrac{ 2\dfrac{1}{4} }{ \dfrac{30}{60} } \\ \\ = \dfrac{9}{4} \div \dfrac{30}{60} \\ \\ = \dfrac{9}{4} \times \frac{60}{30} \\ \\ = 4.5$

4.5 miles per hour.

Hope this helps. - M

5 0

3 years ago

2 = negitive X What does X equal?

kiruha [24]

X is a varible it equals 1 or is used in the expression

6 0

3 years ago

Use the Distributive Property to expand 6(-4x + 3y).

Anna11 [10]

Answer:

-24x + 18y

Step-by-step explanation:

6 x -4x = -24x

6 x 3y = 18y

7 0

3 years ago

An isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long. How long are t

djverab [1.8K]

Answer: The value of other side is 7.8 inch.

Explanation:

It is given that the isosceles triangle has angle measures 50°, 50°, and 80°. The side across from the 80° angle is 10 inches long.

Let the given length of other equal sides be x.

The side across from the 50° angle is x inches long.

Law of sine,

$\frac{a}{\sin A}= \frac{b}{\sin B} =\frac{c}{\sin C}$

$\frac{x}{\sin (50)}= \frac{10}{\sin (80)}$

$\frac{x}{0.766} =\frac{10}{0.9848}$

$x =\frac{10}{0.9848}\times (0.766)$

$x =7.778229 \approx 7.8$

Therefore, the value of other side is 7.8 inch.

3 0

4 years ago

Read 2 more answers

Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.

Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

the points will be clustered according to their distance to the centroids.
Then centroids are updated as the cluster means.
This process continues until clusters doesn't change anymore

1) initial centroids 10-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

new centroids 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

final centroids 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = $(18-6)^{2}$ + $(18-12)^{2}$ + $(18-18)^{2}$ + $(18-24)^{2}$ + $(18-30)^{2}$ + $(45-42)^{2}$ + $(45-48)^{2}$ =378

2)initial centroids 10-20

first cluster (6,12) mean:9

second cluster (18,24,30,42,48) mean:32.4

new centroids 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

new centroids 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

final centroids 15-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

Sum of Squared errors = $(15-6)^{2}$ + $(15-12)^{2}$ + $(15-18)^{2}$ + $(15-24)^{2}$ + $(40-30)^{2}$ + $(40-42)^{2}$ + $(40-48)^{2}$ =348

6 0

4 years ago