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lawyer [7]
3 years ago
12

Which of the following is a solution to sin(x/2) = radical 3/2

Mathematics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

sin ( x/ 2 )  =  - √ 3 /2

Take the inverse sine of both sides of the equation to extract  x

from inside the sine.

x/ 2 = arcsin ( − √ 3/ 2 )

The exact value of  arcsin ( − √ 3 /2 )  is  − π /3 .

/x 2 = − π /3

Multiply both sides of the equation by  2 .

2 ⋅ x /2 = 2 ⋅ ( − π /3 )

Simplify both sides of the equation.

x = − 2 π /3

The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from  2 π , to find a reference angle. Next, add this reference angle to  π  to find the solution in the third quadrant.

x /2 = 2 π + π/ 3 + π

Simplify the expression to find the second solution.  

x = 2 π /3  

4 π

Add  4 π  to every negative angle to get positive angles.  

x = 10 π /3

The period of the  sin ( x /2 )  function is  4 π  so values will repeat every  4 π  radians in both directions.

x =2 π /3 + 4 π n , 10 π/ 3 + 4 π n , for any integer  n

Exclude the solutions that do not make  sin ( x /2 ) = − √ 3/ 2  true.

x = 10 π /3 + 4 π n , for any integer  n

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Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

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\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
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\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

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Answer:

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