Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
2p + q = 1
9p + 3q + 3 = 0
q = 1 - 2p
replace q = 1 - 2p into 9p + 3q + 3 = 0
9p + 3(1 - 2p) + 3 = 0
9p + 3 - 6p + 3 = 0
3p + 6 =0
3p = -6
p = -2
q = 1 - 2p
q = 1 -2(-2)
q = 1 + 4
q = 5
(-2 , 5)
there for the answer would be
{(-2, 5)}
Hopefully this was helpful <3 :3
Answer:
The second one if that how to answer.
Step-by-step explanation:
Answer:
Null Hypothesis, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute
Alternate Hypothesis, H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute
Step-by-step explanation:
The null hypothesis is basically the problem statement i.e
Pulse rates of men have a standard deviation equal to 10 beats per minute
Hence, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute
The alternate hypothesis will contradict or negate the null hypothesis i.e
H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute
She has 24 pieces, 8x3=24.
Plz rate 5 stars
