Two trains leave towns 798 kilometers apart at the same time and travel toward each other. One train travels 22 kmh slower than

Question

3 years ago

11

the other. If they meet in 3 hours, what is the rate of each train?

1 answer:

Vikentia [17] · Answer 1 · 2022-04-29T10:58:37+03:00

The rate of faster train is 144 kilometer per hour and rate of slower train is 122 kilometers per hour.

Step-by-step explanation:

Given,

Total distance = 798 kilometers

Let,

speed of faster train = x

speed of slower train = x-2

Time = 3 hours

Distance = Speed*Time

Distance covered by faster train = 3x

Distance covered by slower train = 3(x-22) = 3x-66

As they both traveled combined distance, therefore,

$3x+(3x-66)=798\\3x+3x-66=798\\6x=798+66\\6x=864$

Dividing both sides by 6

$\frac{6x}{6}=\frac{864}{6}\\x=144$

The speed of faster train is 144 km/h

Speed of slower train = x-22 = 144-22 = 122 km/h

The rate of faster train is 144 kilometer per hour and rate of slower train is 122 kilometers per hour.

Keywords: distance, speed

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