Answer:
3040
Step-by-step explanation:
given arithmetic progression is
70,100,130,...
here
first term (a)=70
common difference (d)=100-70=30
number of term n=100
using the formula of arithmetic progression
an=a+(n-1)d
a100=70+(100-1)30
a100=70+99×30
a100=70+2970
a100=3040
Answer:
The total cost of 1 belt and 1 tie is $13 and $39 respectively.
Step-by-step explanation:
Given that,
The cost of 4 belts and 5 ties is $247.
Each tie costs 3 times as much as a belt.
Let the cost of a belt is x and that of a tie is y.
ATQ,
4x + 5y = 247 ...(1)
y = 3x ....(2)
Put the value of y from equation (2) in equation (1)
4x + 5(3x) = 247
4x + 15x = 247
19x = 247
x = 13
Put the value in equation (2)
y = 3x
= 3(13)
= 39
So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.
Answer:
648
Step-by-step explanation:
A=Ph
P=perimeter of triangle
P=6+6+6
P=18
h= height of prism
h=38
A=ph
A=18*36
A=648
