Lily has 2 Vegetable pizzas from Pizza Hut. She cuts the pizzas
1 answer:
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I can see it goes through the point (2, 2)
b = 6 then
solved it the lazy way, graphically with desmos and a slider for b, see screenshot
Answer:
The function has 2 zeros:
Step-by-step explanation:
When you have a polynomial function, you can identify the grade of the function (the grade is the maximum potency) and this is the number of zeros that the function will have. In this case, you have a second-grade polynomial function that has 2 zeros.
To solve this we are going to use the exponential function: 
where
is the final amount after 
years
is the initial amount
is the decay or grow rate rate in decimal form
is the time in years
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate, we are going to use the formula: 
*100%
*100%
*100%
5%
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
*100%
*100
*100%
*100%
12%
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.
where
Expression A
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at
We can conclude that the initial value of expression A is 624.
Expression B
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at
The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.