There are infinitely many solutions.
Algebraically, we can eliminate
and try to solve for
:

Then



which is the equation of an ellipse.
Answer:
238 + 122 – 28 = 332
There were 332 unbroken eggs left.
332 – 126 = 206
There were 206 white eggs left
Answer:

Given:

To find:

Step-by-step explanation:

Multiply 2x-5y= -21 by 3 to make it 6x-15y= -63
Multiply 3x-3y= -18 by -5 to make it -15x+15y=90
This cancels the y’s out which leaves us with
6x=-63
&
-15x=90
x for 6x=-63 equals - 10.5 so x is - 10.5 and for -15x=90, x= -6
Then you plug in x into any equation you’d like to find y.
Let’s plug in - 10.5 into 6x... equation.
6(- 10.5)-15y=-63
63-15y= -63
-63 -63
-15y=0
y=0 and x= - 10.5. When you plug in this values it makes the equation true!
But the correct answer is the first one north. Sorry if I’m doing too much hahah
If I’m confusing here’s the right answer...
6x-15y= -63
-15x+15y=90