Question

An isosceles triangle has base length 18 cm and height 4cm what is the approximate length of the two other sides

Answer 1

Answer:

The approximate length of the two other sides is 10cm

Step-by-step explanation:

Given

$Base\ Length = 18$

$Height = 4$

Required

The length of the two other sides

Divide the triangle to 2 (See attachment)

Considering one of the triangles, we have:

$l^2 = 4^2 + 9^2$

$l^2 = 16 + 81$

$l^2 = 97$

Take square roots

$l = \sqrt{97$

$l = 9.8488$

$l = 10$ --- approximated