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2 years ago

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Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to

the left, the magnitude of the acceleration of the object is 1.30 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.600 m/s2 to the right. Find the magnitudes of the two forces P and Q in newtons.

1 answer:

trapecia [35]2 years ago

8 0

Answer:

P = 2.45 N

Q = 6.65 N

Explanation:

According to Newton's 2nd Law:

Unbalanced Force = ma

where,

m = mass = 7 kg

a = acceleration

In the first case when both forces P and Q act on left side:

Unbalanced Force = P + Q

a = 1.3 m/s²

Therefore,

P + Q = (7 kg)(1.3 m/s²)

P + Q = 9.1 N ------------------------- equation 1

Now, in second case when both forces have different directions:

Unbalanced Force = Greater Force - Smaller Force

Unbalanced Force = Q - P

a = 0.6 m/s²

Therefore,

Q - P = (7 kg)(0.6 m/s²)

Q - P = 4.2 N ------------------- equation 2

Adding equation 1 and equation 2, we get:

(Q + P) + (Q - P) = 9.1 N + 4.2 N

2 Q = 13.3 N

<u>Q = 6.65 N</u>

Using this value in equation 2, we get:

6.65 N - P = 4.2 N

<u>P = 2.45 N</u>

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Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s

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Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

$58 m/s - 9.8 m/s^2 *4.6 s = v0 = 12.92 m/s$

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

$y0 + v0*t + 1/2 g *t^2 = yt$

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$0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m$

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2 years ago

4 (JAMB) The diagram below shows a light see-saw, which is balanced horizontally by the weights W₁, W2, W3, W4 in the positions

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The equation that represents the principle of the lever balance is:

W₁ + W₂ = W3 + W4; option A.

<h3>What is the principle of moments?</h3>

The principle of moments states when a body is in equilibrium, the sum of the clockwise moment about a point equals the sum of anticlockwise moment about that point.

A see-saw represents a balanced system of moments.

The sum of clockwise moment = The sum of anticlockwise moments.

Assuming W1 and W2 are clockwise moments and W3 and W4 are anticlockwise moments.

The equation will b: W₁ + W₂ = W3 + W4

In conclusion, a balanced see-saw illustrates the principle of the lever balance.

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1 year ago

A ceiling fan has three blades. The moment of inertia of a blade is 0.2kgm^2. The net torque exerted on fan blades is 8Nm. Find

olchik [2.2K]

Answer:

(A) the angular acceleration of the blades is 13.33 m/s.

Explanation:

Given;

moment of inertia of a blade, I = 0.2 kgm²

net torque exerted on fan blades, ∑τ = 8Nm

Torque is given as product of moment of inertia and angular acceleration;

τ = Iα

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α is the angular acceleration

Since there are three blades of the ceiling fan, the net torque is given as;

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2 years ago

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an

AveGali [126]

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

$\phi=123.75$

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From the question we are told that:

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Time $t=75sec$

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Therefore

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Therefore

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3 years ago