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Assuming that there were no encumbrances during it's foreswing and it reached it's full potential at apogee.
This electric force calculator will enable you to determine the repulsive or attractive force between two static charged particles. Continue reading to get a better understanding of Coulomb's law, the conditions of its validity, and the physical interpretation of the obtained result.
How to use Coulomb's law
Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges. It is repulsive if both charges have the same sign and attractive if they have opposite signs.
Coulomb's law is formulated as follows:
F = keq₁q₂/r²
where:
F is the electrostatic force between charges (in Newtons),
q₁ is the magnitude of the first charge (in Coulombs),
q₂ is the magnitude of the second charge (in Coulombs),
r is the shortest distance between the charges (in m),
ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N·m²/C². This value is already embedded in the calculator - you don't have to remember it :)
Simply input any three values
Answer: Friction
Explanation:
The friction force is the force exerted by a surface as an object moves across it or makes an effort to move across it. There are at least two types of friction force - sliding and static friction. Though it is not always the case, the friction force often opposes the motion of an object.
Answer:
Magnetic substances: steel tank, iron ball, nickel hinge
Non magnetic substances: wooden table, glass marbles, silver medal.
Explanation:
The substances which experience a force of attraction when placed in a magnetic field are called magnetic substances. For example, iron, cobalt and nickel.
The substances which do not experiences a force of attraction when placed in a magnetic field are called non magnetic substances. For example, wood, rubber, glass, etc.
Answer:
The correct answer is option 'c': 30 AUs
Explanation:
For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

This energy per unit area is sensed by observer as intensity of the sun.
Let the initial intensity of sun at a distance
be 
Thus if the sun becomes 900 times dimmer we have

Thus the distance increases 30 times.